0,25x^2-5x+25-2x=0

Solution for 0,25x^2-5x+25-2x=0 equation:

0.25x^2-5x+25-2x=0

We add all the numbers together, and all the variables

0.25x^2-7x+25=0

a = 0.25; b = -7; c = +25;
Δ = b2-4ac
Δ = -72-4·0.25·25
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-2\sqrt{6}}{2*0.25}=\frac{7-2\sqrt{6}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+2\sqrt{6}}{2*0.25}=\frac{7+2\sqrt{6}}{0.5}
$